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360=480x^2
We move all terms to the left:
360-(480x^2)=0
a = -480; b = 0; c = +360;
Δ = b2-4ac
Δ = 02-4·(-480)·360
Δ = 691200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{691200}=\sqrt{230400*3}=\sqrt{230400}*\sqrt{3}=480\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-480\sqrt{3}}{2*-480}=\frac{0-480\sqrt{3}}{-960} =-\frac{480\sqrt{3}}{-960} =-\frac{\sqrt{3}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+480\sqrt{3}}{2*-480}=\frac{0+480\sqrt{3}}{-960} =\frac{480\sqrt{3}}{-960} =\frac{\sqrt{3}}{-2} $
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